数组的常用算法
冒泡排序
        
        int[] a1 = {8,3,5,6,9};
        for (int i = a1.length-1; i > 0; i--) {
            for (int j = 0; j < i; j++) {
                if (a1[j] > a1[j+1]) {
                    int temp = 0;
                    temp = a1[j];
                    a1[j] = a1[j+1];
                    a1[j+1] = temp;
                }
            }
        }
选择排序
int[] a2 = {7,8,3,2};
        for (int i = 0; i < a2.length-1; i++) {
            int min = i;
            for (int j = i+1; j < a2.length; j++) {
                if (a2[min] > a2[j]) {
                    min = j;
                }
            }
            if (min!=i) {
                int temp = 0;
                temp = a2[i];
                a2[i] = a2[min];
                a2[min] = temp;
            }
        }
二分法查找(折半查找)
    public static int binarySearch(int[] a,int destElement) {
        
        int begin = 0;
        
        int end = a.length-1;
        while (begin<=end) {
            
            int mid = (begin+end)/2;
            if (a[mid] == destElement) {
                return mid;
            }else if(a[mid] > destElement) {
                end = mid-1;
            }else if(a[mid] < destElement) {
                begin = mid + 1;
            }
        }
        return -1;
    }